Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 8 - Cumulative Review: 33

Answer

The solutions are-$\frac{1}{2}$ or 4

Work Step by Step

x(2x-7)=4 2$x^{2}$-7x-4=0 2$x^{2}$-8x+x-4=0 2x(x-4)+1(x-4)=0 (2x+1)(x-4)=0 2x+1=0 or x-4 =0 x=-$\frac{1}{2}$ or x=4 The solutions are-$\frac{1}{2}$ or 4 Check Let x=-$\frac{1}{2}$ x(2x-7)=4 -$\frac{1}{2}$ [2(-$\frac{1}{2}$) -7]=4 -$\frac{1}{2}$ [-1 -7]=4 -$\frac{1}{2}$ [-8]=4 4=4 Let x=4 x(2x-7)=4 4(2$\times4$-7)=4 4(8-7)=1 4=4
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