Answer
$\dfrac{4x+1}{3x+1}$
Work Step by Step
$\dfrac{4+x^{-1}}{3+x^{-1}}=\dfrac{4+\dfrac{1}{x}}{3+\dfrac{1}{x}}=\dfrac{\dfrac{4x+1}{x}}{\dfrac{3x+1}{x}}=\dfrac{x(4x+1)}{x(3x+1)}=\dfrac{4x+1}{3x+1}$
Algebra: A Combined Approach (4th Edition)
by Martin-Gay, Elayn
Published by
Pearson
ISBN 10:
0321726391
ISBN 13:
978-0-32172-639-1
Chapter 7 - Section 7.7 - Simplifying Complex Fractions - Exercise Set - Page 550: 54
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