Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 7 - Section 7.7 - Simplifying Complex Fractions - Exercise Set: 54

Answer

$\dfrac{4x+1}{3x+1}$

Work Step by Step

$\dfrac{4+x^{-1}}{3+x^{-1}}=\dfrac{4+\dfrac{1}{x}}{3+\dfrac{1}{x}}=\dfrac{\dfrac{4x+1}{x}}{\dfrac{3x+1}{x}}=\dfrac{x(4x+1)}{x(3x+1)}=\dfrac{4x+1}{3x+1}$
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