#### Answer

$\frac{-26}{3}$

#### Work Step by Step

$\frac{2x+1}{7}$=$\frac{x-3}{5}$
5(2x+1)=7(x-3)
10x+5=7x-21
10x-7x=-21-5
3x=-26
$\frac{-26}{3}$
Check the solution
$\frac{2x+1}{7}$=$\frac{x-3}{5}$
$\frac{2(\frac{-26}{3})+1}{7}$=$\frac{\frac{-26}{3}-3}{5}$
5[2*($\frac{-26}{3}$)+1]=7[$\frac{-26}{3}$-3]
5($\frac{-52}{3}$+$\frac{3}{3}$)=7($\frac{-26}{3}$-$\frac{9}{3}$)
5($\frac{-49}{3}$)=7($\frac{-35}{3}$)
($\frac{-245}{3}$)=($\frac{-245}{3}$)