Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 7 - Section 7.6 - Proportions and Problem Solving with Rational Equations - Practice: 2



Work Step by Step

$\frac{2x+1}{7}$=$\frac{x-3}{5}$ 5(2x+1)=7(x-3) 10x+5=7x-21 10x-7x=-21-5 3x=-26 $\frac{-26}{3}$ Check the solution $\frac{2x+1}{7}$=$\frac{x-3}{5}$ $\frac{2(\frac{-26}{3})+1}{7}$=$\frac{\frac{-26}{3}-3}{5}$ 5[2*($\frac{-26}{3}$)+1]=7[$\frac{-26}{3}$-3] 5($\frac{-52}{3}$+$\frac{3}{3}$)=7($\frac{-26}{3}$-$\frac{9}{3}$) 5($\frac{-49}{3}$)=7($\frac{-35}{3}$) ($\frac{-245}{3}$)=($\frac{-245}{3}$)
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