Chapter 7 - Section 7.5 - Solving Equations Containing Rational Expressions - Practice - Page 521: 4

$x=-1$

$\frac{2}{x+3}+\frac{3}{x-3}=\frac{-2}{x^2-9}$ $\frac{2(x-3)}{(x+3)(x-3)}+\frac{3(x+3)}{(x-3)(x+3)}=\frac{-2}{x^2-9}$ $\frac{2x-6}{(x+3)(x-3)}+\frac{3x+9}{(x-3)(x+3)}=\frac{-2}{x^2-9}$ $\frac{2x-6}{x^2-9}+\frac{3x+9}{x^2-9}=\frac{-2}{x^2-9}$ $2x-6+3x+9=-2$ $5x+3=-2$ $5x=-5$ $5x/5=-5/5$ $x=-1$