#### Answer

x = -6

#### Work Step by Step

$\frac{x+2}{3}$-$\frac{x-1}{5}$=$\frac{1}{15}$
15($\frac{x+2}{3}$-$\frac{x-1}{5}$)=15$\frac{1}{15}$
15$\frac{x+2}{3}$-15$\frac{x-1}{5}$=15$\frac{1}{15}$
5(x+2)-3(x-1)=1
5x+10-3x+3=1
2x+13=1
2x=1-13
2x=-12
x= -6
Check
$\frac{x+2}{3}$-$\frac{x-1}{5}$=$\frac{1}{15}$
$\frac{-6+2}{3}$-$\frac{-6-1}{5}$=$\frac{1}{15}$
$\frac{-4}{3}$-$\frac{-7}{5}$=$\frac{1}{15}$
15$\frac{-4}{3}$-15$\frac{-7}{5}$=15$\frac{1}{15}$
5(-4)-3(-7)=1
-20+21=1
1=1