Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 7 - Section 7.5 - Solving Equations Containing Rational Expressions - Practice: 2


x = -6

Work Step by Step

$\frac{x+2}{3}$-$\frac{x-1}{5}$=$\frac{1}{15}$ 15($\frac{x+2}{3}$-$\frac{x-1}{5}$)=15$\frac{1}{15}$ 15$\frac{x+2}{3}$-15$\frac{x-1}{5}$=15$\frac{1}{15}$ 5(x+2)-3(x-1)=1 5x+10-3x+3=1 2x+13=1 2x=1-13 2x=-12 x= -6 Check $\frac{x+2}{3}$-$\frac{x-1}{5}$=$\frac{1}{15}$ $\frac{-6+2}{3}$-$\frac{-6-1}{5}$=$\frac{1}{15}$ $\frac{-4}{3}$-$\frac{-7}{5}$=$\frac{1}{15}$ 15$\frac{-4}{3}$-15$\frac{-7}{5}$=15$\frac{1}{15}$ 5(-4)-3(-7)=1 -20+21=1 1=1
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