#### Answer

x-2

#### Work Step by Step

$\frac{x^{2}+9x}{x+7}$-$\frac{4x+14}{x+7}$=
$\frac{x^{2}+9x-(4x+14)}{x+7}$=
$\frac{x^{2}+9x-4x-14}{x+7}$=
$\frac{x^{2}+5x-14}{x+7}$=
$\frac{x^{2}+7x-2x-14}{x+7}$=
$\frac{x(x+7)-2(x+7)}{x+7}$=
$\frac{(x-2)(x+7))}{x+7}$= x-2