Answer
$\frac{xy(xy-1)}{12}$
Work Step by Step
$(\frac{x^2y^2-xy}{4x-4y}\div\frac{3y-3x}{8x-8y})*\frac{y-x}{8}$
$\frac{x^2y^2-xy}{4x-4y}*\frac{8x-8y}{3y-3x}*\frac{y-x}{8}$
$\frac{xy(xy-1)}{4(x-y)}*\frac{8(x-y)}{3(y-x)}*\frac{y-x}{8}$
$\frac{xy(xy-1)}{4}*\frac{8}{3(y-x)}*\frac{y-x}{8}$
$\frac{xy(xy-1)}{12}*\frac{1}{(y-x)}*\frac{y-x}{1}$
$\frac{xy(xy-1)}{12}*\frac{1}{1}*\frac{1}{1}$
$\frac{xy(xy-1)}{12}$
