Answer
$\dfrac{3-\dfrac{1}{y}}{2-\dfrac{1}{y}}=\dfrac{3y-1}{2y-1}$
Work Step by Step
$\dfrac{3-\dfrac{1}{y}}{2-\dfrac{1}{y}}$
Evaluate the substractions indicated in the numerator and in the denominator:
$\dfrac{3-\dfrac{1}{y}}{2-\dfrac{1}{y}}=\dfrac{\dfrac{3y-1}{y}}{\dfrac{2y-1}{y}}=...$
Evaluate the division and simplify if possible:
$...=\dfrac{3y-1}{y}\div\dfrac{2y-1}{y}=\dfrac{y(3y-1)}{y(2y-1)}=\dfrac{3y-1}{2y-1}$
