Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 6 - Test - Page 477: 20



Work Step by Step

$x^{2}+5x=14$ Subtract: $14$ from both sides: $x^{2}+5x-14=14-14$ $x^{2}+5x-14=0$. $x^{2}-2x+7x-14=0$ $x^{2}-2x+7x-14=0$ $x(x-2)+7(x-2)=0$ $(x-2)(x+7)=0$ $(x-2)=0$ or $(x+7)=0$ $x=2$ or $x=-7$. Therefore, $x=-7,2$.
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