Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 6 - Section 6.7 - Quadratic Equations and Problem Solving - Exercise Set - Page 467: 36

Answer

7.75 seconds

Work Step by Step

$h=-16t^2+961$ $0=-16t^2+961$ $0*-1=(-16t^2+961)*-1$ $0=16t^2-961$ $0=(4t+31)(4t-31)$ $4t+31=0$ $4t=-31$ $4t/4=-31/4$ $t=-31/4$ (invalid since we can't have a negative time) $4t-31=0$ $4t=31$ $4t/4=31/4$ $t=31/4$
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