Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 6 - Section 6.7 - Quadratic Equations and Problem Solving - Exercise Set - Page 465: 11

Answer

base = 16 miles, height = 6 miles

Work Step by Step

$a=b*h$ $96 = (x+5)(x-5)$ $96 = x^2+5x-5x-25$ $96 = x^2-25$ $121 = x^2$ $\sqrt {121} = \sqrt {x^2}$ $x = ± 11$ ($x\ne-11$ since we can't have a negative side length. Thus, $x=11$) $(x+5)(x-5)$ $(11+5)(11-5)$ $16*6$
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