Answer
the solutions are $0$ , $3$ and $-3$
Work Step by Step
We simplify as follows:
$2x^{3}-18x=0$
$2x(x^{2}-9)=0$
$2x(x-3)(x+3)=0$
$2x=0$ or $x-3=0$ or $x+3=0$
$x=0$ or $x=3$ or $x=-3$
Algebra: A Combined Approach (4th Edition)
by Martin-Gay, Elayn
Published by
Pearson
ISBN 10:
0321726391
ISBN 13:
978-0-32172-639-1
Chapter 6 - Section 6.6 - Solving Quadratic Equations by Factoring - Practice - Page 456: 7
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