Algebra: A Combined Approach (4th Edition)

by Martin-Gay, Elayn

Published by Pearson

ISBN 10: 0321726391

ISBN 13: 978-0-32172-639-1

Chapter 6 - Section 6.5 - Factoring by Special Products - Practice - Page 444: 9

Answer

$(a-3)(a+3)(a^2+9)$

Work Step by Step

$a^4-81$ $a^4-81=(a^2)^2-9^2$ $a^4-81 = (a^2-9)(a^2+9)$ $(a^2-9)=(a)^2-(3)^2$ $(a^2-9)=(a-3)(a+3)$ $(a-3)(a+3)(a^2+9)$

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