Answer
$3*(2x-1)(2x+1)(4x^2+1)$
Work Step by Step
$48x^4-3$
$3(16x^4-1)$
$16x^4-1$
$16x^4-1=(4x^2)^2-1^2$
$16x^4-1=(4x^2-1)(4x^2+1)$
$3*(4x^2-1)(4x^2+1)$
$4x^2-1$
$4x^2-1=(2x)^2-1^2$
$4x^2-1 = (2x-1)(2x+1)$
$3*(2x-1)(2x+1)(4x^2+1)$
Algebra: A Combined Approach (4th Edition)
by Martin-Gay, Elayn
Published by
Pearson
ISBN 10:
0321726391
ISBN 13:
978-0-32172-639-1
Chapter 6 - Section 6.5 - Factoring by Special Products - Practice - Page 444: 11
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