Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 6 - Section 6.3 - Factoring Trinomials of the Form ax2+bx+c - Practice - Page 432: 2


2x²-11x+12= (2x-3)(x-4) 6x²-5x+1= (3x-1)(2x-1)

Work Step by Step

We know that the second factors must both be negative because the c value is positive and the b value is negative. This leaves (2x-3)(x-4) because after the -4 is multiplied with the 2x and -3 with the x, then summed. It adds to -11, the b value. The same is true for the second problem.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.