Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 6 - Section 6.2 - Factoring Trinomials of the Form x2+bx+c - Exercise Set - Page 430: 88

Answer

$(y-5)(y+3)(x+1)$

Work Step by Step

$y^2(x+1)-2y(x+1)-15(x+1)$ $=(y^2-2y-15)(x+1)$ $=(y^2+3y-5y-15)(x+1)$ $=[y(y+3)-5(y+3)](x+1)$ $=(y-5)(y+3)(x+1)$
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