## Algebra: A Combined Approach (4th Edition)

Chapter 6 - Section 6.2 - Exercise Set: 79 (Answer) For $x^2 + bx + c$ = $(x + p)(x + q)$, since ‘c’ is the product of the respective constant term of the two binomials (c = $p\cdot q$), if ‘c’ is negative, either p or q must be negative. So, the signs of the last-term factors of the binomials are opposite.
Chapter 6 - Section 6.2 - Exercise Set: 79 (Solution) Explanation : As $x^2 + bx + c$ is factorable, it can be written as $x^2 + bx + c$ = $(x + p)(x + q)$ Since ‘c’ is the product of the respective constant term of the two binomials (c = $p\cdot q$), if ‘c’ is negative, either p or q must be negative. So, the signs of the last-term factors of the binomials are opposite.