Answer
FALSE
Work Step by Step
$3x^3+6x+x^2+2 = 3x(x^2+2) + 1(x^2+2) = (3x + 1)(x+3)$
The factor form is $(3x + 1)(x+3)$
and not $ 3x(x^2+2) $
because : $ 3x(x^2+2) = 3x^2 + 6x \ne 3x^3+6x+x^2+2$
for example $x=1$
$ 3x(x^2+2) = 9 \ne 12 = 3x^3+6x+x^2+2$