#### Answer

$\frac{1}{5}a^2(2a^3-4a+1)$

#### Work Step by Step

$\frac{2}{5}a^5 - \frac{4}{5}a^3 + \frac{1}{5}a^2 = \frac{1}{5}a^2(2a^3-4a+1)$

Published by
Pearson

ISBN 10:
0321726391

ISBN 13:
978-0-32172-639-1

$\frac{1}{5}a^2(2a^3-4a+1)$

$\frac{2}{5}a^5 - \frac{4}{5}a^3 + \frac{1}{5}a^2 = \frac{1}{5}a^2(2a^3-4a+1)$

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