"whose product is $-48$ and whose sum is $2$"
Work Step by Step
Given $x^2+2x-48$ if we factor this expression we have that: $x^2+2x-48 = (x+8)(x-6)$ and the product of $8$ and $-6$ is $-48$, while the sum of $8$ and $-6$ is $2$
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