Answer
$x=4$ or $x=9$
Work Step by Step
$x^{2}-13x=-36$
Adding $36$ to both sides, $x^{2}-13x+36=-36+36$.
Simplifying, $x^{2}-13x+36=0$.
$x^{2}-4x-9x+36=0$
$x(x-4)-9(x-4)=0$
$(x-4)(x-9)=0$
$(x-4)=0$ or $(x-9)=0$
$x=4$ or $x=9$
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