Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 5 - Section 5.7 - Dividing Polynomials - Exercise Set: 34

Answer

$m^2n-n^3$

Work Step by Step

$\frac{m^3n^2-mn^4}{mn}$ $=m^3n^2(\frac{1}{mn})-mn^4(\frac{1}{mn})$ $=m^2n-n^3$
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