Work Step by Step
Substracting $y^2+2$ from $3y^2-6y+1$ we have: $(3y^2-6y+1)-(y^2+2)=(3y^2-6y+1)+[-(y^2+2)]$ $(3y^2-6y+1)+(-y^2-2)=3y^2-6y+1-y^2-2$ $2y^2-6y-1$
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