Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 5 - Section 5.5 - Multiplying Polynomials - Practice - Page 377: 10

Answer

$3{y^4} - 12{y^3} + 16{y^2} - 4y + 5$

Work Step by Step

$(3{y^2} + 1) ({y^2} - 4y +5)$ = $({y^2} -4y + 5)$ * $ (3{y^2} +1)$ = ${y^2} -4y +5$ +$3{y^4} - 12{y^3} + 15{y^2}$ =$ 3{y^4} - 12{y^3} + 15 {y^2} + {y^2} - 4y +5$ = $3{y^4} - 12{y^3} + 16{y^2} - 4y + 5$
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