## Algebra: A Combined Approach (4th Edition)

$13x-9$
Substract $(3x+1)$ from the sum of $(4x-3)$ and $(12x-5)$ This expression can be translated to: $[(4x-3)+(12x-5)]-(3x+1)$ First, evaluate the sum inside the brackets: $[(4+12)x-(5+3)]-(3x+1)=(16x-8)-(3x+1)=...$ Remove both parentheses. To remove the second one, change the sign of every term inside it: $...=16x-8-3x-1=...$ Simplify by combining like terms: $...=(16-3)x-(8+1)=13x-9$