Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 5 - Section 5.4 - Adding and Subtracting Polynomials - Exercise Set: 11

Answer

$\dfrac{1}{2}m^{2}-\dfrac{7}{10}m+\dfrac{13}{16}$

Work Step by Step

$\Big(\dfrac{3}{4}m^{2}-\dfrac{2}{5}m+\dfrac{1}{8}\Big)+\Big(-\dfrac{1}{4}m^{2}-\dfrac{3}{10}m+\dfrac{11}{16}\Big)$ Remove both parentheses: $\dfrac{3}{4}m^{2}-\dfrac{2}{5}m+\dfrac{1}{8}-\dfrac{1}{4}m^{2}-\dfrac{3}{10}m+\dfrac{11}{16}=...$ Simplify by combining like terms: $...=\Big(\dfrac{3}{4}-\dfrac{1}{4}\Big)m^{2}-\Big(\dfrac{2}{5}+\dfrac{3}{10}\Big)m+\Big(\dfrac{1}{8}+\dfrac{11}{16}\Big)=...$ $...=\dfrac{2}{4}m^{2}-\dfrac{20+15}{50}m+\dfrac{16+88}{128}=...$ $...=\dfrac{1}{2}m^{2}-\dfrac{35}{50}m+\dfrac{104}{128}=...$ $...=\dfrac{1}{2}m^{2}-\dfrac{7}{10}m+\dfrac{13}{16}$
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