Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 5 - Section 5.3 - Introduction to Polynomials - Exercise Set - Page 366: 57

Answer

$14y^{3}-16a^{2}b^{2}-19$

Work Step by Step

$14y^{3}-9+3a^{2}b^{2}-10-19b^{2}a^{2}$ Rewrite this expression by putting the $a$ of the fifth term right after the coefficient: $14y^{3}-9+3a^{2}b^{2}-10-19a^{2}b^{2}=...$ Simplify by combining like terms: $...=14y^{3}+(3-19)a^{2}b^{2}-(9+10)=...$ $...=14y^{3}-16a^{2}b^{2}-19$
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