Answer
$\frac{49}{36}$
Work Step by Step
We know that $a^{−n}=\frac{1}{a^{n}}$ and $\frac{1}{a^{-n}}=a^{n}$ (as long as a is a nonzero real number and n is an integer).
Therefore, $(\frac{6}{7})^{-2}=\frac{1}{6^{2}}\times7^{2}=\frac{49}{36}$.
Algebra: A Combined Approach (4th Edition)
by Martin-Gay, Elayn
Published by
Pearson
ISBN 10:
0321726391
ISBN 13:
978-0-32172-639-1
Chapter 5 - Section 5.2 - Negative Exponents and Scientific Notation - Practice - Page 348: 5
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