Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 5 - Section 5.1 - Exponents - Practice: 33

Answer

a.$ x^{3}$ b. $81y^{16}$ c. $\frac{x^3}{64}$

Work Step by Step

a. When dividing $x^{7}$ by $x^{4}$, you simply subtract the exponents because the base number/variable is the same. So 7-4 equals 3. b.$(3y^{4})^4$ Simply multiply the exponent by the base number within the parentheses. 3 has an understood exponent of 1. y has an exponent of 4. $3^4$ equals 81. $(y^4)^4$ equals $y^{16}$. c. This is similar to the last problem. x gets cubed, so it's $x^3$. 4 gets cubed as well, which equals 64. It remains as a fraction and can't be reduced.
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