Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 5 - Section 5.1 - Exponents - Practice - Page 342: 33


a.$ x^{3}$ b. $81y^{16}$ c. $\frac{x^3}{64}$

Work Step by Step

a. When dividing $x^{7}$ by $x^{4}$, you simply subtract the exponents because the base number/variable is the same. So 7-4 equals 3. b.$(3y^{4})^4$ Simply multiply the exponent by the base number within the parentheses. 3 has an understood exponent of 1. y has an exponent of 4. $3^4$ equals 81. $(y^4)^4$ equals $y^{16}$. c. This is similar to the last problem. x gets cubed, so it's $x^3$. 4 gets cubed as well, which equals 64. It remains as a fraction and can't be reduced.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.