Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 5 - Section 5.1 - Exponents - Practice - Page 341: 29



Work Step by Step

We know that $a^{0}=1$, as long as $a$ is not 0. Therefore, $(2r^{2}s)^{0}=1$, where $a=2r^{2}s$.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.