Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 5 - Section 5.1 - Exponents - Practice: 10

Answer

$\frac{1}{81}$

Work Step by Step

$(-\frac{1}{9})^2$ = $-\frac{1}{9}\times-\frac{1}{9}$ 2 negatives make a positive $(-\frac{1}{9})^2$ = $\frac{1}{81}$ $\frac{1}{81}$
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