## Algebra: A Combined Approach (4th Edition)

$\frac{1}{81}$
$(-\frac{1}{9})^2$ = $-\frac{1}{9}\times-\frac{1}{9}$ 2 negatives make a positive $(-\frac{1}{9})^2$ = $\frac{1}{81}$ $\frac{1}{81}$