Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 5 - Section 5.1 - Exponents - Exercise Set: 120

Answer

3, 6, 6, 2

Work Step by Step

Based on the power rule for exponents, we know that $(a^{m})^{n}=a^{mn}$ (where $m$ and $n$ are positive integers and $a$ is a real number). Therefore, $(y^{3})^{6}\times(y^{6})^{2}=y^{3\times6}\times y^{6\times2}=y^{18}\times y^{12}$. Based on the product rule for exponents, we know that $a^{m}\times a^{n}=a^{m+n}$ (where $m$ and $n$ are positive integers and $a$ is a real number). Therefore, $y^{18}\times y^{12}=y^{18+12}=y^{30}$.
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