## Algebra: A Combined Approach (4th Edition)

$\dfrac{(2x^{6}y^{2})^{5}}{-32x^{20}y^{10}}=-x^{10}$
$\dfrac{(2x^{6}y^{2})^{5}}{-32x^{20}y^{10}}$ First, evaluate the exponential expression in the numerator: $\dfrac{(2x^{6}y^{2})^{5}}{-32x^{20}y^{10}}=\dfrac{32x^{30}y^{10}}{-32x^{20}y^{10}}=...$ Evaluate the division: $\Big(\dfrac{32}{-32}\Big)x^{30-20}y^{10-10}=-x^{10}y^{0}=-x^{10}$