Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 5 - Section 5.1 - Exponents - Exercise Set: 106

Answer

$\dfrac{(2x^{6}y^{2})^{5}}{-32x^{20}y^{10}}=-x^{10}$

Work Step by Step

$\dfrac{(2x^{6}y^{2})^{5}}{-32x^{20}y^{10}}$ First, evaluate the exponential expression in the numerator: $\dfrac{(2x^{6}y^{2})^{5}}{-32x^{20}y^{10}}=\dfrac{32x^{30}y^{10}}{-32x^{20}y^{10}}=...$ Evaluate the division: $\Big(\dfrac{32}{-32}\Big)x^{30-20}y^{10-10}=-x^{10}y^{0}=-x^{10}$
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