Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 5 - Section 5.1 - Exponents - Exercise Set: 34


$18y^{17}$ meters

Work Step by Step

We are given that the parallelogram has base length of $9y^{7}$ meters and height of $2y^{10}$ meters. We know that the area of a parallelogram is calculated as $area=base \times height$. Based on the product rule for exponents, we know that $a^{m}\times a^{n}=a^{m+n}$ (where $m$ and $n$ are positive integers and $a$ is a real number). Therefore, $area=9y^{7}\times2y^{10}=9\times2\times y^{7+10}=18y^{17}$ meters.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.