Answer
$\frac{b^{3}}{27a^{6}}$
Work Step by Step
$(\frac{3a^2}{b})^{-3}$
$=\frac{3^{-3}a^{2\times -3}}{b^{-3}}$
$=\frac{3^{-3}a^{-6}}{b^{-3}}$
$=\frac{b^{3}}{3^{3}a^{6}}$
$=\frac{b^{3}}{27a^{6}}$
Algebra: A Combined Approach (4th Edition)
by Martin-Gay, Elayn
Published by
Pearson
ISBN 10:
0321726391
ISBN 13:
978-0-32172-639-1
Chapter 5 - Review - Page 412: 39
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