Answer
$4a-1+\frac{2}{a^2}-\frac{5}{2a^3}$
Work Step by Step
$\frac{8a^4-2a^3+4a-5}{2a^3}$
$=8a^4(\frac{1}{2a^3})-2a^3(\frac{1}{2a^3})+4a(\frac{1}{2a^3})-5(\frac{1}{2a^3})$
$=4a-1+\frac{2}{a^2}-\frac{5}{2a^3}$
Algebra: A Combined Approach (4th Edition)
by Martin-Gay, Elayn
Published by
Pearson
ISBN 10:
0321726391
ISBN 13:
978-0-32172-639-1
Chapter 5 - Review - Page 407: 140
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