Answer
Answer:
When:
t=0 seconds,
Height from the Ground: = 4000 feet
When:
t=1 seconds,
Height from the Ground: = 3984 feet .
When:
t=3 seconds,
Height from the Ground = 3856 feet.
When:
t=5 seconds,
Height from the Ground = 3600 feet.
Work Step by Step
For calculating the height of an object dropped from the Skywalk,
The given formula is: height from the ground : $h = -16t^{2}+4000$
So,
When:
t=0 seconds,
Height from the Ground: $h = -16t^{2}+4000$ = -16(0)+4000 = 4000 feet.
When:
t=1 seconds,
Height from the Ground: $h = -16\times(1)^{2}+4000$ = -16(1)+4000 = 3984 feet.
When:
t=3 seconds,
Height from the Ground: $h = -16\times(3)^{2}+4000$ = -16(9)+4000 = -144+4000 = 3856 feet .
When:
t=5 seconds,
Height from the Ground: $h = -16\times(5)^{2}+4000$ = -16(25)+4000 = -400 + 4000 = 3600 feet .
