Chapter 5 - Review: 65

Answer: When: t=0 seconds, Height from the Ground: = 4000 feet When: t=1 seconds, Height from the Ground: = 3984 feet . When: t=3 seconds, Height from the Ground = 3856 feet. When: t=5 seconds, Height from the Ground = 3600 feet.

Work Step by Step

For calculating the height of an object dropped from the Skywalk, The given formula is: height from the ground : $h = -16t^{2}+4000$ So, When: t=0 seconds, Height from the Ground: $h = -16t^{2}+4000$ = -16(0)+4000 = 4000 feet. When: t=1 seconds, Height from the Ground: $h = -16\times(1)^{2}+4000$ = -16(1)+4000 = 3984 feet. When: t=3 seconds, Height from the Ground: $h = -16\times(3)^{2}+4000$ = -16(9)+4000 = -144+4000 = 3856 feet . When: t=5 seconds, Height from the Ground: $h = -16\times(5)^{2}+4000$ = -16(25)+4000 = -400 + 4000 = 3600 feet .

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