## Algebra: A Combined Approach (4th Edition)

$x=\frac{-1}{2}$
$2x+\frac{1}{8}=x-\frac{3}{8}$ Subtracting $x$ from both sides, $2x-x+\frac{1}{8}=x-x-\frac{3}{8}$ $x+\frac{1}{8}=-\frac{3}{8}$. Subtracting $\frac{1}{8}$ from both sides, $x+\frac{1}{8}-\frac{1}{8}=-\frac{3}{8}-\frac{1}{8}$ $x=-\frac{3}{8}-\frac{1}{8}$ $x=\frac{-3-1}{8}$ $x=\frac{-4}{8}$ $x=\frac{-1}{2}$