Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 4 - Test - Page 330: 11

Answer

$$x=20$$ $$y=8$$

Work Step by Step

Equation 1: $x + y = 28$ Equation 2: $x - y = 12$ Add equation 1 and 2: $$x + y = 28$$ $$+$$ $$x - y = 12$$ $$=$$ $$2x=40$$ Divide both sides by $2$: $$\frac{2x}{2}=\frac{40}{2}$$ $$x=20$$ Substitute this value of $x$ to equation 1: $$x + y = 28$$ $$20 + y = 28$$ Subtract $20$ from both sides: $$20 -20+ y = 28-20$$ $$y=8$$ Use equation 2 to check: $$x - y = 12$$ $$20 - 8 = 12$$ $$12=12$$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.