#### Answer

$x=3$
$y=1$

#### Work Step by Step

$\begin{cases} 4x+y=13\\2x-y=5\end{cases}$
Add both equations to eliminate the $y$:
$6x=18$
Solve for $x$:
$x=\dfrac{18}{6}=3$
Substitute $x=3$ in the first equation:
$4(3)+y=13$
Solve for $y$:
$12+y=13$
$y=13-12=1$
Our solutions are:
$x=3$
$y=1$