## Algebra: A Combined Approach (4th Edition)

$x=3$ $y=1$
$\begin{cases} 4x+y=13\\2x-y=5\end{cases}$ Add both equations to eliminate the $y$: $6x=18$ Solve for $x$: $x=\dfrac{18}{6}=3$ Substitute $x=3$ in the first equation: $4(3)+y=13$ Solve for $y$: $12+y=13$ $y=13-12=1$ Our solutions are: $x=3$ $y=1$