## Algebra: A Combined Approach (4th Edition)

Published by Pearson

# Chapter 4 - Section 4.2 - Solving Systems of Linear Equations by Substitution - Exercise Set: 25

x = -1 y = -4

#### Work Step by Step

3x - y =1 2x - 3y = 10 minus 3x to both sides to the first equation 3x - y - 3x = 1 - 3x -y = 1 - 3x multiply by ( -1) to both sides y = -1 + 3x substitude y to the second equation 2x - 3 ( -1 +3x ) = 10 use the distributive property 2x + 3 - 9x = 10 simplify - 7x + 3 = 10 minus 3 to both sides -7x + 3 - 3 = 10 - 3 simplify - 7x = 7 divide both sides by -7 $\frac{-7x}{-7}$ = $\frac{7}{-7}$ x = -1 substitude x to y = -1 + 3x y = -1 + $3\times(-1)$ y = -1 -3 y = -4

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