Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 3 - Section 3.5 - Equations of Lines - Exercise Set - Page 256: 78

Answer

$$y=\frac{1}{2}x-2$$

Work Step by Step

$$y = -2x + 3$$ This equation is in the form $y=mx+b$ with $m$ as slobe and $b$ as y-intercept. Since parallel lines have have opposite slopes (negative reciprocals), then the equation we are looking for will have a slope=$\frac{1}{2}$. Thus, we have: $$y=\frac{1}{2}x+b$$ We can now use the given point $(4, 0)$ to find the y-intercept, $b$. $$y=\frac{1}{2}x+b$$ $$0=\frac{1}{2} (4)+b$$ $$0=2+b$$ Subtracting $2$ from both sides: $$0=2+b$$ $$0-2=2-2+b$$ $$-2=b$$ The equation will now become: $$ y=\frac{1}{2}x-2$$ Plotting both equations will give us:
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