Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 3 - Section 3.4 - Slope and Rate of Change - Exercise Set - Page 241: 84

Answer

a. $(2002, 1210)$ $(2008, 2350)$ b. $190$ c. The price of an acre of farmland increases by $190$ dollars per year.

Work Step by Step

a. Let $x$ be the year. Let $y$ be the average price of an acre of U.S. farmland. $(2002, 1210)$ $(2008, 2350)$ b. $\frac{2350-1210}{2008-2002}=\frac{1140}{6}=190$ c. The slope in this case means the change in price of an acre of farmland per year. In this case, the price increases by 190 dollars per year.
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