## Algebra: A Combined Approach (4th Edition)

a. $m_{parallel}=\frac{9}{11}$. b. $m_{perpendicular}=-\frac{11}{9}$
A line parallel to the line that passes through the points (-8, -4) and (3, 5) will have a slope of $m_{parallel}=\frac{5-(-4)}{3-(-8)}=\frac{9}{11}$. A line perpendicular to the line that passes through the points (-8, -4) and (3, 5) will have a slope of $m_{perpendicular}=-\frac{11}{9}$ (the negative reciprocal).