## Algebra: A Combined Approach (4th Edition)

Point A: $y=\frac{1}{2}x+3$ $y=\frac{1}{2}(0)+3$ $y=3$ Point B: $y=\frac{1}{2}x+3$ $y=\frac{1}{2}(-4)+3$ $y=-2+3$ $y=1$ Point C: $y=\frac{1}{2}x+3$ $0=\frac{1}{2}x+3$ $-3=\frac{1}{2}x$ $x=-6$
To find the coordinates of Point A and B, substitute the given x-values into the given formula $y=\frac{1}{2}x+3$ to find the y-value for the corresponding x-values. To find the coordinates of Point C, substitute the given y-value into the given formula $y=\frac{1}{2}x+3$ to find the x-value for the corresponding x-value. When all three points are found, plot each point on the graph provided and draw a straight line, which represents (graphically) the given formula $y=\frac{1}{2}x+3$ .