## Algebra: A Combined Approach (4th Edition)

Published by Pearson

# Chapter 3 - Review - Page 274: 42

Perpendicular

#### Work Step by Step

$y=6x-\frac{1}{3}$ $x+6y=6$ $6y=-x+6$ $y=-\frac{1}{6}x+1$ The coefficients of $x$ for both equations are not the same, so the slopes are different. This means this pair of lines is not parallel. For a pair of lines to be perpendicular to each other, the slope of one equation must be the negative reciprocal of the other. $6$ and $-\frac{1}{6}$ are negative reciprocals of each other. This means this pair of lines is perpendicular.

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