#### Answer

$x\leq\frac{8}{3}$

#### Work Step by Step

$5(x+4)\geq4(2x+3)$
$5x+20\geq8x+12$
$-3x\geq-8$
$x\leq\frac{8}{3}$

Published by
Pearson

ISBN 10:
0321726391

ISBN 13:
978-0-32172-639-1

$x\leq\frac{8}{3}$

$5(x+4)\geq4(2x+3)$
$5x+20\geq8x+12$
$-3x\geq-8$
$x\leq\frac{8}{3}$

You can help us out by revising, improving and updating this answer.

Update this answerAfter you claim an answer you’ll have **24 hours** to send in a draft. An editor
will review the submission and either publish your submission or provide feedback.