Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 2 - Section 2.7 - Linear Inequalities and Problem Solving - Exercise Set - Page 173: 67

Answer

1160 minutes

Work Step by Step

$200\div5,8=1160$ You have to divide the complete amount of calories by the amount of calories burn in one minute and you'll end up with the time the person will take to burn this much. $c\div\frac{c}{m}=m$
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