Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 2 - Section 2.6 - Percent and Mixture Problem Solving - Exercise Set: 23

Answer

2 gallons of pure acid should be mixed with 2 gallons of a 40% acid solution to get a 70% acid solution.

Work Step by Step

number of gallons × acid strength = amount of acid x=# of gallons Gallons of pure acid = x Gallons of 40% acid = 2 Gallons of 70% acid needed = x + 2 $1x+0.40(2)=0.70(x+2)$ $1x+0.80=0.70x + 1.40$ $1x-0.70x = 1.40-0.80$ $0.30x=0.60$ $x=0.60\div0.30$ $x=2$
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