#### Answer

$t=\dfrac{10}{9}$

#### Work Step by Step

$\dfrac{3}{4}t-\dfrac{1}{2}=\dfrac{1}{3}$
Add $\dfrac{1}{2}$ to both sides of the equation:
$\dfrac{3}{4}t-\dfrac{1}{2}+\dfrac{1}{2}=\dfrac{1}{3}+\dfrac{1}{2}$
$\dfrac{3}{4}t=\dfrac{2+3}{6}$
$\dfrac{3}{4}t=\dfrac{5}{6}$
To get the solution, multiply both sides of the equation by $\dfrac{4}{3}$:
$\Big(\dfrac{3}{4}t\Big)\Big(\dfrac{4}{3}\Big)=\dfrac{5}{6}\Big(\dfrac{4}{3}\Big)$
$t=\dfrac{20}{18}=\dfrac{10}{9}$